k^2-4=(-36)

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Solution for k^2-4=(-36) equation: 



k^2-4=(-36)

We move all terms to the left:

k^2-4-((-36))=0

We add all the numbers together, and all the variables

k^2+32=0

a = 1; b = 0; c = +32;
Δ = b2-4ac
Δ = 02-4·1·32
Δ = -128
Delta is less than zero, so there is no solution for the equation

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